×
Please submit new Bug Reports on GitHub: github.com/Jensen-Technologies/component-creator-issues/issues
Show on list view no longer working correctly
alex
Fresh Boarder
Posts: 2
7 Jahre 10 Monate her #1470
von alex
Show on list view no longer working correctly wurde erstellt von alex
I have a field J_SQL
It is a select of virtuemart products.
On the list view it always has shown the "selected" product. ie the value in the database.
Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
It is a select of virtuemart products.
On the list view it always has shown the "selected" product. ie the value in the database.
Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
Bitte Anmelden oder Registrieren um der Konversation beizutreten.
Chris
Fresh Boarder
Posts: 3
7 Jahre 9 Monate her #1484
von Chris
Chris antwortete auf Show on list view no longer working correctly
I see same problem. I checked my database, data is saving correctly, but showing incorrectly on admin list view.
Bitte Anmelden oder Registrieren um der Konversation beizutreten.
Chris
Fresh Boarder
Posts: 3
7 Jahre 9 Monate her #1485
von Chris
Chris antwortete auf Show on list view no longer working correctly
I was able to adjust the query in the list model, adding a left join, grabbing the correct data. Then I edited the view file, showing the "name" rather than the "id" of the field in question. This challenged my SQL skills, but solved the problem.
Bitte Anmelden oder Registrieren um der Konversation beizutreten.
alex
Fresh Boarder
Posts: 2
7 Jahre 9 Monate her #1487
von alex
alex antwortete auf Show on list view no longer working correctly
so how did you solve this?
can you post it here?
can you post it here?
Bitte Anmelden oder Registrieren um der Konversation beizutreten.
Chris
Fresh Boarder
Posts: 3
7 Jahre 9 Monate her #1490
von Chris
Chris antwortete auf Show on list view no longer working correctly
Alex, Something like this...
let's say you have "items" and "parents". You want to show a list of items with the correct parent name.
Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.
Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.
Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.
I had to brush up on MySql joins as well as the JDatabase query() object.
As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.
As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.
That's as specific as I can explain, hope it helps.
let's say you have "items" and "parents". You want to show a list of items with the correct parent name.
Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.
Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.
Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.
I had to brush up on MySql joins as well as the JDatabase query() object.
As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.
As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.
That's as specific as I can explain, hope it helps.
Folgende Benutzer bedankten sich: Andres Maeso
Bitte Anmelden oder Registrieren um der Konversation beizutreten.
Ladezeit der Seite: 0.054 Sekunden